kdtree模板题
我判是否查询时用mid来判没有存极值,然后貌似被卡常了?
hzwer的代码在我本地的随机数据中跑得没我快...难道bzoj上的数据有构造的?
//By Richard #include <cstdio> #include <algorithm> #include <iostream> #include <cstring> #include <cstdlib> #include <cmath> #include <ctime> #define rep(x,y,z) for (int x=(y);(x)<=(z);(x)++) #define per(x,y,z) for (int x=(y);(x)>=(z);(x)--) #define log2(x) (31-__builtin_clz(x)) #define mod (int)(1e9+7) #define inf 0x3f3f3f3f #define cls(x) memset(x,0,sizeof(x)) #ifdef DEBUG #define debugdo(X) X #define debugndo(X) #define debugout(X) cout<<(#X)<<"="<<(X)<<endl #else #define debugdo(X) #define debugndo(X) X #define debugout(X) #endif // debug #ifdef ONLINE_JUDGE #define debugdo(X) #define debugndo(X) X #define debugout(X) #endif #define putarray(x,n) rep(iiii,1,n) printf("%d ",x[iiii]) #define mp make_pair using namespace std; typedef pair<int,int> pairs; typedef long long LL; /////////////////////read3.0//////////////////////////////////// template <typename T> inline void read(T &x){char ch;x=0;bool flag=false;ch=getchar();while (ch>'9'||ch<'0') {ch=getchar();if (ch=='-') flag=true;}while ((ch<='9'&&ch>='0')){x=x*10+ch-'0';ch=getchar();}if (flag) x*=-1;} template <typename T> inline void read(T &x,T &y){read(x);read(y);} /////////////////variables&functions//////////////////// const int maxn=1111111; int n,doing,m,ans; bool now; struct POINT { int x,y; }point[maxn]; struct Node { Node *l,*r; int id; inline bool operator<(const Node &other)const { if (now) return point[id].x<point[other.id].x; else return point[id].y<point[other.id].y; } }node[maxn]; struct kd_tree { Node *root; // Node node[maxn]; inline void init(const int &vv) { rep(i,1,vv) node[i].id=i; } Node *build(const int &l,const int &r,const bool &d) { if (l==r) return node+l; else if (l>r) return 0; now=d; int mid=(l+r)>>1; nth_element(node+l,node+mid,node+r+1); node[mid].l=build(l,mid-1,d^1); node[mid].r=build(mid+1,r,d^1); return &node[mid]; } inline void insert(const int &x) { // doing=x; node[x].id=x; Node *nowp=root; bool now=1; while (1) { if (now) { if (point[x].x<point[nowp->id].x) { if (nowp->l) nowp=nowp->l; else { nowp->l=&node[x]; break; } } else { if (nowp->r) nowp=nowp->r; else { nowp->r=&node[x]; break; } } } else { if (point[x].y<point[nowp->id].y) { if (nowp->l) nowp=nowp->l; else { nowp->l=&node[x]; break; } } else { if (nowp->r) nowp=nowp->r; else { nowp->r=&node[x]; break; } } } now^=1; } } inline int dis(const int &x) { return abs(point[x].x-point[doing].x)+abs(point[x].y-point[doing].y); } void querycore(const Node *x,const bool &d) { // now=d; ans=min(ans,dis(x->id)); if (d) { if (point[x->id].x>point[doing].x) { if (x->l) querycore(x->l,d^1); if (point[x->id].x-point[doing].x<ans&&x->r) querycore(x->r,d^1); } else { if (x->r) querycore(x->r,d^1); if (point[doing].x-point[x->id].x<ans&&x->l) querycore(x->l,d^1); } } else { if (point[x->id].y>point[doing].y) { if (x->l) querycore(x->l,d^1); if (point[x->id].y-point[doing].y<ans&&x->r) querycore(x->r,d^1); } else { if (x->r) querycore(x->r,d^1); if (point[doing].y-point[x->id].y<ans&&x->l) querycore(x->l,d^1); } } } inline int query(const int &x) { ans=inf; doing=x; querycore(root,1); return ans; } }kdtree; int main() { read(n,m); kdtree.init(n+m); rep(i,1,n) read(point[i].x,point[i].y); kdtree.root=kdtree.build(1,n,1); int tt; rep(i,n+1,n+m) { read(tt); read(point[i].x,point[i].y); if (tt==2) printf("%d\n",kdtree.query(i)); else kdtree.insert(i);} return 0;
}